3a^2+26a+5=-2a^2

Solution for 3a^2+26a+5=-2a^2 equation:

3a^2+26a+5=-2a^2

We move all terms to the left:

3a^2+26a+5-(-2a^2)=0

We get rid of parentheses

3a^2+2a^2+26a+5=0

We add all the numbers together, and all the variables

5a^2+26a+5=0

a = 5; b = 26; c = +5;
Δ = b2-4ac
Δ = 262-4·5·5
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-24}{2*5}=\frac{-50}{10}
=-5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+24}{2*5}=\frac{-2}{10}
=-1/5
$